Static Pressure or Head in Fluids

Pressure indicates the normal force per unit area at a given point acting on a given plane. Since there is no shearing stresses present in a fluid at rest - the pressure in a fluid is independent of direction.

For fluids - liquids or gases - at rest the pressure gradient in the vertical direction depends only on the specific weight of the fluid.

How pressure changes with elevation can be expressed as

dp = - γ dz                                            (1)

where

dp = change in pressure (Pa, psi)

dz = change in height (m, in)

γ = specific weight (N/m3, lb/ft3)

The pressure gradient in vertical direction is negative - the pressure decrease upwards.

Specific Weight

Specific Weight can be expressed as:

γ = ρ g                                             (2)

where

ρ = density (kg/m3, slugs/ft3)

g = acceleration of gravity (9.81 m/s2, 32.174 ft/s2)

In general the specific weight - γ - is constant for fluids. For gases the specific weight - γ - varies with elevation.

The pressure exerted by a static fluid depends only upon

• the depth of the fluid
• the density of the fluid
• the acceleration of gravity

Static Pressure in a Fluid

For a incompressible fluid - as a liquid - the pressure difference between two elevations can be expressed as:

p2 - p1 = - γ (z2 - z1)                                     (3)

where

p2 = pressure at level 2  (Pa, psi)

p1 = pressure at level 1   (Pa, psi)

z2 = level 2    (m, ft)

z1 = level 1   (m, ft)

(3) can be transformed to:

p1 - p2 = γ (z2 - z1)                                      (4)

or

p1 - p2 = γ h (5)

where

h = z2 - z1 difference in elevation - the dept down from location z2     (m, ft)

or

p1 = γ h + p2                                           (6)

Example - Pressure in a Fluid

The absolute pressure at water depth of 10 m can be calculated as:

p1 = γ h + p2

= (1000 kg/m3) (9.81 m/s2) (10 m) + (101.3 kPa)

= (98100 kg/ms2 or Pa) + (101300 Pa)

= 199.4 kPa

where

ρ = 1000 kg/m3

g = 9.81 m/s2

p2 = pressure at surface level = atmospheric pressure = 101.3 kPa

The gauge pressure can be calculated by setting p2 = 0

p1 = γ h + p2

= (1000 kg/m3) (9.81 m/s2) (10 m)

= 98.1 kPa

(6) can be transformed to:

h = (p2 - p1) / γ                                                (7)

h express the pressure head - the height of a column of fluid of specific weight - γ - required to give a pressure difference of (p2 - p1).

A pressure difference of 5 psi (lbf/in2) is equivalent to

(5 lbf/in2) (12 in/ft) (12 in/ft) / (62.4 lb/ft3)

= 11.6  ft of water

(5 lbf/in2) (12 in/ft) (12 in/ft) / (847 lb/ft3)

= 0.85  ft of mercury

when specific weight of water is 62.4 (lb/ft3) and specific weight of mercury is 847 (lb/ft3).

Heads at different velocities are indicated in the table below:

Velocity
(ft/sec)
(ft)
0.5 0.004
1.0 0.016
1.5 0035
2.0 0.062
2.5 0.097
3.0 0.140
3.5 0.190
4.0 0.248
4.5 0.314
5.0 0.389
5.5 0.470
6.0 0.560
6.5 0.657
7.0 0.762
7.5 0.875
8.0 0.995
8.5 1.123
9.0 1.259
9.5 1.403
10.0 1.555
11.0 1.881
12.0 2.239
13.0 2.627
14.0 3.047
15.0 3.498
16.0 3.980
17.0 4.493
18.0 5.037
19.0 5.613
20.0 6.219
21.0 6.856
22.0 7.525
• 1 ft (foot) = 0.3048 m = 12 in = 0.3333 yd

Related Topics

• Fluid Mechanics - The study of fluids - liquids and gases. Involves velocity, pressure, density and temperature as functions of space and time
• Pumps - Piping systems and pumps - centrifugal pumps, displacement pumps - cavitation, viscosity, head and pressure, power consumption and more

Tag Search

• en: pressure head static fluid liquid
• es: presión de carga de líquido fluido estático
• de: Druckkopf statischen Fluidflüssigkeit

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