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Pumps, Fans and Turbines - Horsepower

British Horse Power as used for pumps, fans and turbines - and how to convert to other units.

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Horsepower is the imperial (British) unit of power. A horsepower is the ability to do work at the rate of

  • 33000 per min or
  • 550 per second

Note that Power is "Work per unit time" and work is "Force through distance". In gravity systems the Force is Weight - mass multiplied with gravity.

In the SI system the unit of power is watt (W, Nm/s, J/s).

The total horsepower developed by water falling from a given height is the product of the mass flow rate in pounds per minute times the falling height in feet divided by 33000 and can be expressed as:

Php = mmin h ag / 33000                                 (1)


Php = power (horsepower, hp)

mmin = mass flow rate per minute (lbm/min)

h = head or height (ft)

ag = acceleration of gravity (32 ft/s2)

(1) can alternatively be expressed as:

Php = msec h ag / 550                                (1b)


msec = mass flow rate per second (lbm/s)

(1) can also be expressed as:

Php = γ Q h / 33000                                 (1c)


Q = volume flow rate (ft3/min)

γ = specific weight (lbf/ft3) (weight is force)

Water Horsepower for Flow in gal/min

Water horsepower for flow in gal/min can be expressed as:

Pwhp = SG Qgal h / 3960         (1d)


Q = volume flow rate (gpm)

SG = specific gravity

h = head (ft)

SG for water is 1.001 at 32oF and 0.948 at 240oF.

SG - Specific Gravity

Qgal - Volume Flow (imp gpm)

h - head (ft)

Power to Pump Water

Required horsepower (hp) to pump 1 cubic foot of water per minute (ft3/min) with efficiency 85% - is indicated in the diagram below:

Pumping water - horsepower versus head

  • 1 hp (English horse power) = 745.7 W
  • 1 ft (foot) = 0.3048 m

Example - Required Power to lift 10 ft3/min of Water 600 ft

According the diagram above 1 hp is required to lift 1 ft3/min of water 600 ft. Required power to pump 10 ft3/min can be calculated as

(10 ft3/min) (1 hp) / (1 ft3/min) = 10 hp

Shaft or Brake Horsepower

The brake horsepower is the amount of real horsepower going to the pump, not the horsepower used by the motor. In the metric system kilowatts (kW) is used.

Due to hydraulic, mechanical and volumetric losses in a pump or turbine the actual horsepower available for work on or from the fluid is less than the total horsepower supplied.

Shaft or Brake Horsepower for a Pump or Fan

The brake horse power - bhp - for a pump or fan can be expressed as:

Pbhp = ( γ Q h / 33000 ) / η                               (2)


Pbhp = brake horse power (horsepower, hp)

Q = volume flow rate (ft3/min, cfm)

η = overall efficiency

Shaft or Brake Horsepower for a Turbine

The brake horse power - bhp - for a turbine can be expressed as:

Pbhp = η ( γ Q h / 33000 )                              (2b)

Input Horsepower to the Electrical Motor

The input horsepower to the electrical motor for a pump or fan can be expressed as:

Php_el = Pbhp / ηe         (3)


Php_el = (m h g / 33000) / (η ηe)         (3b)


Php_el = input power to the electrical motor

ηe = mechanical efficiency of the electrical motor

Horsepower in Kilowatts and other Units

Horsepower can be converted to other common units as:

  • 1 hp (English horse power) = 745.7 W = 0.746 kW = 550 = 2545 Btu/h = 33000 = 1.0139 metric horse power

Transforming horsepower to kW:

PkW = 0.746 Php                             (4)


PkW = power (kW)

Together with the equations above it's possible to express (4) in many common combinations - such as:

PkW = 0.746 (m h / 33000) / η ηe                             (5)

Example - Pump Power

The horsepower required to pump 50 lbm/min water a head of 10 ft with a pump with overall efficiency 0.7 - can be calculated with eq. (3) as

Php = ((50 lbm/min)(10 ft) (32 ft/s2) / 33000) / 0.8

       = 0.6 hp

The power in kW can be calculated as 

PkW = 0.746 (0.6 hp)

       = 0.45 kW

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  • Engineering ToolBox, (2003). Pumps, Fans and Turbines - Horsepower. [online] Available at: [Accessed Day Mo. Year].

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