# Line slope calculator 5x+2y=50

**Straight line given by points A[6; 10] and B[8; 5]**

## Calculation:

**Slope-intercept form of line:**y = -2.5x+25

**Canonical form of the line equation:**5x+2y-50 = 0

**Parametric form of the line equation:**

x = 2t+6

y = -5t+10 ; t ∈ R

**Slope:**m = -2.5

**Slope angle of line: φ =**-68°11'55″ = -1.1903 rad

**X intercept:**x

_{0}= 10

**Y intercept:**y

_{0}= q = 25

**Distance line from the origin:**d

_{0}= 9.2848

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(2; -5)

**Normal vector: n =**(5; 2)

**Midpoint of the segment AB: M =**[7; 7.5]

**Perpendicular Bisector equation:**2x-5y+23.5 = 0

**Vector OA = (6; 10) ; |OA| = 11.6619**

**Vector OB = (8; 5) ; |OB| = 9.434**

**Scalar product OA .OB = 98**

**Angle ∠ AOB = 27°1'51″ = 0.4718 rad**