The force exerted by a single acting pneumatic cylinder with 1 bar (105 N/m2) and full bore diameter of 100 mm (0.1 m) can be calculated as
F = p π d2 / 4
= (105 N/m2) π (0.1 m)2 / 4
= 785 N
= 0.785 kN
The force exerted by double acting pneumatic cylinder on outstroke can be expressed as (1). The force exerted on instroke can be expressed as
F = p π (d12 - d22) / 4 (2)
d1 = full bore piston diameter (m)
d2 = piston rod diameter (m)
The force exerted from a single acting pneumatic cylinder with 1 bar (105 N/m2), full bore diameter of 100 mm (0.1 m) and rod diameter 10 mm (0.01 m) can be calculated as
F = p π (d12 - d22) / 4
= (105 N/m2) π [(0.1 m)2 - (0.01 m)2] / 4
= 778 N
= 0.78 kN
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