# Pneumatic Cylinder - Excerted Force vs. Pressure

## Force excerted by pneumatic air cylinders vs. air pressure cylinder size - online calculator.

### Single Acting Cylinder

The force exerted by a single acting pneumatic cylinder can be expressed as

F = p A

= p π d^{2 }/ 4 (1)

where

F = force exerted (N)

p = gauge pressure (N/m^{2}, Pa)

A = full bore area (m^{2})

d = full bore piston diameter (m)

#### Single Acting Cylinder Calculator - Output Stroke

##### Calculate Force with known Pressure and Diameter

*Pressure (kPa) (1 bar = 100 kPa)*

*Cylinder Diameter (mm)*

##### Calculate required Diameter with known Force and Pressure

*Force (N)*

*Pressure (kPa)*

##### Calculate required Pressure with known Force and Diameter

*Force (N)*

*Diameter (mm)*

#### Example - Single Acting Piston

The force exerted by a single acting pneumatic cylinder with *1 bar (10 ^{5} N/m^{2})* and full bore diameter of

*100 mm (0.1 m)*can be calculated as

F = p π d^{2 }/ 4

= (10^{5}N/m^{2}) π (0.1 m)^{2}/ 4

= 785 N

= 0.785 kN

### Air Cylinder - Pressure/Force Diagram

#### SI-units

#### Imperial Units

### Double Acting Cylinder

The force exerted by double acting pneumatic cylinder on outstroke can be expressed as (1). The force exerted on instroke can be expressed as

F = p π (d_{1}^{2}- d_{2}^{2}) / 4 (2)

where

d_{1}= full bore piston diameter (m)

d_{2}= piston rod diameter (m)

#### Double Acting Cylinder Calculator - Input Stroke

##### Calculate Force with known Pressure and Diameter

*Pressure (kPa)*

*Cylinder Diameter (mm)*

*Piston Rod Diameter (mm)*

##### Calculate required Diameter with known Force and Pressure

*Force (N)*

*Pressure (kPa)*

*Piston Rod Diameter (mm)*

##### Calculate required Pressure with known Force and Diameter

*Force (N)*

*Diameter (mm)*

*Piston Rod Diameter (mm)*

#### Example - Double Acting Piston

The force exerted from a single acting pneumatic cylinder with *1 bar (10 ^{5} N/m^{2})*, full bore diameter of

*100 mm (0.1 m)*and rod diameter

*10 mm (0.01 m)*can be calculated as

F = p π (d_{1}^{2}- d_{2}^{2) }/ 4

= (10^{5}N/m^{2}) π [(0.1 m)^{2}- (0.01 m)^{2}] / 4

= 778 N

= 0.78 kN

- instroke capacity is reduced compared to outstroke capacity - due to the rod and reduced active pressurized areal