F c = m a g (4)
When the elevator starts or stops - the acceleration or deceleration force in addition to the constant speed force can be expressed as
F a = m (v 1 - v 0 ) / t a (5)
F a = acceleration force (N, lb f )
v 1 = final velocity (m/s, ft/s)
v 0 = initial velocity (m/s, ft/s)
t a = start or stop (acceleration) time (s)
The power required to move the elevator can be calculated as
P = W / t
= m a g (h 1 - h 0 ) / t (6)
P = power (W, ft lb f )
t = time to move the elevator between levels (s)
An elevator with mass 2000 kg including passengers are moved from level 0 m to level 15 m . The force required to move the elevator at constant speed can be calculated as
F c = (2000 kg) (9.81 m/s 2 )
= 19820 N
The power required to move the elevator between the levels in 20 s can be calculated as
P = (2000 kg) (9.81 m/s 2 ) ((15 m) - (0 m)) / (20 s)
= 14865 W
= 14.9 kW
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