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The evaporation of water from a water surface, as an open tank, a swimming pool or similar, depends the temperature in the water and the temperature in the air, the actual humidity of the air and the velocity of the air above the surface.

The amount of evaporated water can be expressed with the empirical equation as:
g = Θ A (xs - x) (1)
where
g = amount of evaporated water (kg/h)
Θ = (25 + 19 v) = evaporation coefficient (kg/m2h)
v = velocity of air above the water surface (m/s)
A = water surface area (m2)
xs = humidity ratio in saturated air at the same temperature as the water surface (kg/kg)
x = humidity ratio in the air (kg/kg)
Note! The units don't match since the equation is empirical (a result of experiments).
Most of the heat required for the evaporation is taken from the water itself. To maintain the water temperature heat must be supplied.
The heat supplied can be calculated as:
q = hwe g (2)
where
q = heat supplied (kJ/s, kW)
hwe = 2270 - evaporation heat of water (kJ/kg)
For a swimming pool with water temperature 25oC the saturation humidity ratio is 0.019826 kg/kg. With an air temperature of 25oC and 50% relative humidity, the humidity ratio in the air is 0.0115 kg/kg - check the Mollier diagram.
For a 25 m x 20 m swimming pool and 0.5 m/s velocity of air above the surface, the evaporation can be calculated as:
g = ( 25 + 19 (0.5 m/s)) ((25 m) (20 m)) ((0.019826 kg/kg) - (0.0115 kg/kg)) / 3600
= 0.04 kg/s
The heat supply required to maintain the temperature can be calculated as:
q = (2270 kJ/kg) (0.04 kg/s)
= 90.8 kW
The heat supply can be reduced by
Note! During operation time the activity in a swimming pool may increase the evaporation and the need of heat supply dramatically.
To reduce the energy consumption and to avoid moisture damages in the building constructions, its more and more common to use heat recycling devices with heat pumps to move latent heat from the air to the water in the swimming pool.
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