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Latent Heat of Melting for some common Materials

Latent heat of fusion when changing between solid or liquid state for common materials like aluminum, ammonia, glycerin, water and more

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The latent heat of fusion of a substance is

  • the amount of heat required to convert a unit mass of the solid into liquid without change in temperature

The latent heat of melting for some common solids are indicated below:

ProductLatent Heat of Melting
(kJ/kg)(Btu/lbm)
Acetic acid 181 77.8
Acetone 98.3 42.3
Alcohol, ethyl (ethanol) 108 46.4
Alcohol, methyl (methanol) 98.8 42.5
Alcohol, propyl 86.5 37.2
Aluminum 321 138.2
Ammonia 339 146
Aniline 113.5 48.8
Antimony 164 70.5
Benzene 126 54.2
Bismuth 52.9 22.7
Brass 168 72.2
Bromine 66.7 28.7
Cadmium 46 19.8
Carbon disulfide 57.6 24.8
Carbon dioxide 184 79
Carbon tetrachloride 174 74.8
Cast iron 126 54.2
Chloroform 77 33.1
Chromium 134 57.6
Cobalt 243 104.5
Copper 207 89
Decane 201 86.4
Dodecane 216 92.8
Ether 96.2 41.4
Ethyl ether 113 48.6
Ethylene glycol 181 77.8
Glycerine 200 75.6
Gold 67 28.8
Heptane 140 60.2
Hexane 152 65.3
Ice, see Water
Iodine 62.2 26.7
Iron, gray cast 96 41.4
Iron, white cast 138 59.4
Iron, slag 209 90.0
Lead 22.4 9.65
Manganese 155 66.6
Mercury 11.6 5.08
Naphthaline 151 64.9
Nickel 297 127.7
Octane 181 77.8
Paraffin 147 63.2
Phenol 121 52
Phosphrus 21.1 9.1
Platinium 113 48.6
Potassium 59 25.4
Propane 79.9 34.3
Propylene 71.4 30.7
Silver 88.0 37.9
Sulphur 39.2 16.87
Tin 58.5 25.2
Toluene 71.8 30.9
Water, Ice 334 144
Wood's alloy 33.5 14.4
Zinc 118 5.63
  • 1 kJ/kg = 0.4299 Btu/lbm = 0.23884 kcal/kg

Heat Required to Melt a Solid

The heat required to melt a solid can be calculated as

q = Lm m                                              (1)

where 

q = required heat (J, Btu)

Lm = latent heat of melting (J/kg, Btu/lb)

m = mass of substance (kg, lb)

Example - Required Heat to melt Ice to Water

The heat required to melt 10 kg of ice to water can be calculated as

q = Lm m

  = 334 103 (J/kg) 10 (kg)

  = 3340000 (J)

  = 3340 (kJ)

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