Hydraulic Oil Pumps - Required Horsepower

Horsepower required by a hydraulic pump can be calculated as

P_HP = q p / 1714                                                     (1)

where

P_HP = horsepower (HP)

q = flow (gpm)

p = required pressure (psi)

• 1 gpm (US) =6.30888x10^-5 m³/s = 0.227 m³/h = 0.06309 dm³(litre)/s = 2.228x10^-3 ft³/s = 0.1337 ft³/min = 0.8327 gpm (UK)
• 1 psi (lb/in²) = 144 psf (lb_f/ft²) = 6,894.8 Pa (N/m²) = 6.895x10^-3 N/mm² = 6.895x10^-2 bar
• 1 hp = 745.7 W

Example - Hydraulic Pump

The horsepower required by a a pump with flow 20 gpm and 1500 psi increase in pressure can be calculated as

 P_HP = (20 gpm) (1500 psi) / 1714

    = 17.5 HP

Efficiency

Note that the equation above is for a pump with 100% efficiency - which in the practial life is never true. An overall efficiency of 80 - 95% is common. 

The equation above (1) can be modified to 

P_HP = q p / ((μ / 100) 1714)                                        (2)

where

μ = overall efficiency (%)

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Citation

This page can be cited as

• Engineering ToolBox, (2009). Hydraulic Oil Pumps - Required Horsepower. [online] Available at: https://www.engineeringtoolbox.com/hydraulic-pumps-horsepower-d_1464.html [Accessed Day Mo. Year].

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