Solving Quadratic Equation with One Unknown
The quadratic equation can be expressed as
a x2 + b x + c = 0 (1)
which can be solved for the two alternatives of x as
x1,2 = (-b ± (b2 - 4 a c)1/2) / (2 a) (2)
Example - Solving Quadratic Equation
If
a = 1
b = 6
c = 5
then the two alternatives for x can be calculated as
x1 = (-6 + (62 - 4 1 5)1/2) / (2 1)
= -1
x2 = (-6 - (62 - 4 1 5)1/2) / (2 1)
= -5
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