# Latitude and Acceleration of Gravity

## Acceleration of gravity varies with latitude

Acceleration of gravity at sea level related to north-south position on earth (degrees latitude):

### Acceleration of Gravity - *a*_{g} - (ft/s^{2})

_{g}- (ft/s

^{2})

### Acceleration of Gravity - *a*_{g} - *m/s*^{2}

_{g}-

^{2}

### Example - Time for Falling Object to Hit the Ground on the Pole or on the Equator

The distance traveled after some time by a free falling object can be expressed as:

*s = 1/2 a _{g} t^{2}*

*where *

*s = distance (m, ft) *

*a _{g} = acceleration of gravity (m/s^{2}, ft/s^{2}) *

*t = time (s)*

The acceleration of gravity is stronger at the poles than at equator and the equation above can be modified to

*t = (2 s / a _{g})^{1/2}*

The time for an object at level *1 m* to hit the ground on the pole can be calculated as:

*t = (2 (1 m) / (9.832 m/s ^{2}))^{1/2} *

* = 0.4510 s*

The time for an object at level *1 m* to hit the ground on the equator can be calculated as:

*t = (2 (1 m) / (9.78 m/s ^{2}))^{1/2} *

* = 0.4522 s*

## Related Topics

## Related Documents

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