Electrical Formulas

The most common used electrical formulas - Ohms Law and combinations

Common electrical units used in formulas and equations are:

  • Volt - unit of electrical potential or motive force - potential is required to send one ampere of current through one ohm of resistance
  • Ohm - unit of resistance - one ohm is the resistance offered to the passage of one ampere when impelled by one volt
  • Ampere - units of current - one ampere is the current which one volt can send through a resistance of one ohm
  • Watt - unit of electrical energy or power - one watt is the product of one ampere and one volt - one ampere of current flowing under the force of one volt gives one watt of energy
  • Volt Ampere - product of volts and amperes as shown by a voltmeter and ammeter - in direct current systems the volt ampere is the same as watts or the energy delivered - in alternating current systems - the volts and amperes may or may not be 100% synchronous - when synchronous the volt amperes equals the watts on a wattmeter - when not synchronous volt amperes exceed watts - reactive power
  • Kilovolt Ampere - one kilovolt ampere - KVA - is equal to 1000 volt amperes
  • Power Factor - ratio of watts to volt amperes

Electrical Potential - Ohm's Law

Ohm's law can be expressed as:

V = R I         (1a)

V = P / I         (1b)

V = (P R)1/2         (1c)

Electric Current - Ohm's Law

I = V / R         (2a)

I = P / V         (2b)

I = (P / R)1/2         (2c)

Electric Resistance - Ohm's Law

R = V / I         (3a)

R = V2/ P         (3b)

R = P / I2         (3c)

Example - Ohm's law

A 12 volt battery supplies power to a resistance of 18 ohms.

I = (12 V) / (18 Ω)

    = 0.67 (A)

ohm's law

Electric Power

P = V I         (4a)

P = R I2         (4b)

P = V2/ R         (4c)


P = power (watts, W)

V = voltage (volts, V)

I = current (amperes, A)

R = resistance (ohms, Ω)

Electric Energy

Electric energy is power multiplied time, or

W = P t      (5)


W = energy (Ws, J)

t = time (s)

Example - Energy lost in a Resistor

A 12 V battery is connected in series with a resistance of 50 ohm. The power consumed in the resistor can be calculated as

P = (12 V)2 / (50 ohm)

   = 2.9 W

The energy dissipated in 60 seconds can be calculated

E = (2.9 W) (60 s)

  = 174 Ws, J

  = 0.174 kWs

  = 4.8 10-5 kWh

Example - Electric Stove

An electric stove consumes 5 MJ of energy from a 230 V power supply when turned on in 60 minutes.

The power rating of the stove can be calculated as

P = (5 MJ) (106 J/MJ) / ((60 min) (60 s/min))

   = 1389 W

   = 1.39 kW

The current can be calculated

I = (1389 W) / (230 V)

  = 6 ampere

Electrical Motors

Electrical Motor Efficiency

μ = 746 Php / Pinput_w         (6)


μ = efficiency

Php = output horsepower (hp)

Pinput_w = input electrical power (watts)

or alternatively

μ = 746 Php / (1.732 V I PF)         (6b)

Electrical Motor - Power

P3-phase = (V I PF 1.732) / 1,000         (7)


P3-phase = electrical power 3-phase motor (kW)

PF = power factor electrical motor

Electrical Motor - Amps

I3-phase = (746 Php) / (1.732 V μ PF)         (7)


I3-phase = electrical current 3-phase motor (amps)

PF = power factor electrical motor

Related Topics

  • Electrical - Electrical units, amps and electrical wiring, wire gauge and AWG, electrical formulas and motors

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