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Thrust on a Submerged Surface
Force acting on a submerged surface
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The force acting on a submerged surface can be expressed as
F = pa A
= ha ρ g A (1)
where
F = thrust force (N)
pa = average pressure on the surface (Pa)
A = area of submerged surface (m2)
ha = average depth (m)
ρ = density (kg/m3) (water 1000 kg/m3)
g = acceleration of gravity (9.81 m/s2)
Example - Thrust acting on the side of a container
Trust acting on part of the submerged side of a container can be expressed as
F = pa A
= A (pt + pb)/2
= ρ g A (ht + hb)/2 (2)
where
pt = pressure at the top of the submerged surface (Pa)
pb = pressure at the bottom of the submerged surface (Pa)
The thrust on a surface (width 1m, height 2m ) in a water filled container can be calculated as
F = ρ g A (ht + hb)/2
= (1000 kg/m3) (9.81 m/s2) (1 m) (2 m) ((0 m) + (2 m))/2
= 9810 N
Example - Thrust acting on the bottom of a container
Trust acting on the submerged bottom of a container can be expressed as
F = pb A
= ρ g hb A (2b)
The thrust on the bottom (width 1m, length 2m ) in a water filled container can be calculated as
F = ρ g hb A
= (1000 kg/m3) (9.81 m/s2) (2 m) (1 m) (2 m)
= 19620 N
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