Center of gravity of some common bodies
The center of gravity of a volume, area or line is the point at which if the body where suspended would be in balance.
For a symmetrical body of a uniform material the center of gravity would be in the geometric center.
The center of gravity is the center of the circle inscribed in triangle ABC (middle points of the sides of the triangle).
The distance d can be calculated as
d = h (b + c) / 2 (a + b + c) (1)
The center of gravity of a triangel is at the intersection of lines BE and AD. The distance a can be calculated as
a = h / 3 (2)
The center of gravity of a parallelogram is at the intersection of the diagonals.
The center of gravity of a trapezoid can be estimated by dividing the trapezoid in two triangles. The center of gravity will be in the intersection between the middle line CD and the line between the triangles centers of gravity.
The center of gravity of two bodies can be calculated as
b = Q a / (P + Q) (3a)
c = P a / (P + Q) (3b)
Q, P = weight or mass of the bodies (N, kg, lb, slugs)
- en: center gravity primeter area parallelogra
- es: centro de gravedad área primeter parallelogra
- de: Zentrum der Schwerkraft primeter Bereich parallelogra