Specific Volume of Moist Air

Specific volume is defined as the total volume of humid air per mass unit of dry air.

Specific Volume of Moist Air per Mass Unit of Dry Air

Specific volume is defined as the total volume of dry air and water vapor mixture per kg of dry air (SI-units). The specific volume can be expressed as:

v_da = V / m_a (1)

where

v_da = specific volume of moist air per mass unit of dry air (m³/kg)

V = total volume of moist air (m³)

m_a = mass of dry air (kg)

When dry air and water vapor with the same temperature occupies the same volume the equation for an ideal gas can be applied.

p_a V = m_a R_a T (2)

where

p_a = partial pressure air (Pa)

R_a = 286.9 - the individual gas constant air (J/kg.K)

T = temperature of the moist air (K)

Combining (1) and (2):

v_da = R_a T / p_a (3)

The partial pressure of air can be expressed as:

p_a = p - p_w (3b)

where

p = pressure in the humid air (Pa)

p_w = partial pressure water vapor (Pa)

Combining (3) and (2b):

v_da = R_a T / (p - p_w) (3c)

The ideal gas law can also be applied for the water vapor:

p_w V = m_w R_w T (4)

where

p_w = partial pressure water vapor (Pa)

R_w = 455 - the individual gas constant water vapor (J/kg.K)

T = temperature of the moist air (K)

The mass of water vapor can be expressed with the humidity ratio and the mass of air:

m_w = x m_a (5)

where

x = specific humidity or humidity ratio (kg/kg)

Combining (4) and (5):

p_w V = x m_a R_w T (6)

Combining (6) with (1):

v_da = x R_w T / p_w (7)

Transforming (7):

p_w = x R_w T / v_da (8)

Combining (8) with (3c):

v_da = R_a T / (p - (x R_w T / v_da)) (9)

(9) can be transformed to express the specific volume of moist air per unit mass of dry air as:

v_da = (1 + x R_w / R_a) R_a T / p (10)