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The effort force with a lifting wheel can be calculated as
F = W d / D (1)
where
F = effort force (N)
W = m a = weight of body (N)
d = wheel inner diameter (m)
D = wheel outer diameter (m)
m = mass of lifted body (kg)
a = 9.81 (m/s2) acceleration of gravity
A body of mass 100 kg is lifted with a lifting wheel with inner diameter 0.1 m and a outer diameter 0.3 m. The effort force can be calculated as
F = 100 (kg) 9.81 (m/s2) 0.1 (m) / 0.3 (m)
= 327 N
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