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The synchronous speed of an induction motor is based on the supply frequency and the number of poles in the motor winding and can be expressed as:
ω = 2 60 f / n (1)
where
ω = pump shaft rotational speed (rev/min, rpm)
f = frequency (Hz, cycles/sec)
n = number of poles
The rotational speed at different frequencies and number of poles can be listed as:
| Pump shaft rotational speed - ω - (rev/min, rpm) | ||||||
| Frequency - f - (Hz) |
Number of poles - n | |||||
| 2 | 4 | 6 | 8 | 10 | 12 | |
| 10 | 600 | 300 | 200 | 150 | 120 | 100 |
| 20 | 1200 | 600 | 400 | 300 | 240 | 200 |
| 30 | 1800 | 900 | 600 | 450 | 360 | 300 |
| 40 | 2400 | 1200 | 800 | 600 | 480 | 400 |
| 501) | 3000 | 1500 | 1000 | 750 | 600 | 500 |
| 602) | 3600 | 1800 | 1200 | 900 | 720 | 600 |
| 70 | 4200 | 2100 | 1400 | 1050 | 840 | 700 |
| 80 | 4800 | 2400 | 1600 | 1200 | 960 | 800 |
| 90 | 5400 | 2700 | 1800 | 1350 | 1080 | 900 |
| 100 | 6000 | 3000 | 2000 | 1500 | 1200 | 1000 |
With a variable frequency drive its possible to modulate the speed of the motor by changing the frequency supplied to the synchronous motor. The relation between motor speed, frequency and number of poles in the motor can be found in the table above.
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