# Radiation Heat Transfer

## Heat transfer due to emission of electromagnetic waves is known as thermal radiation

Sponsored Links

Heat transfer through radiation takes place in form of electromagnetic waves mainly in the infrared region. Radiation emitted by a body is a consequence of thermal agitation of its composing molecules. Radiation heat transfer can be described by a reference to the so-called **'black body'**.

### The Black Body

A black body is defined as a body that absorbs all radiation that falls on its surface. Actual black bodies don't exist in nature - though its characteristics are approximated by a hole in a box filled with highly absorptive material. The emission spectrum of such a black body was first fully described by Max Planck.

A black body is a hypothetic body that completely absorbs all wavelengths of thermal radiation incident on it. Such bodies do not reflect light, and therefore appear black if their temperatures are low enough so as not to be self-luminous. All blackbodies heated to a given temperature emit thermal radiation.

The radiation energy per unit time from a **blackbody** is proportional to the fourth power of the absolute temperature and can be expressed with **Stefan-Boltzmann Law ** as

q = σ T^{4}A(1)

where

q= heat transfer per unit time (W)

σ= 5.6703 10^{-8}(W/m^{2}K^{4}) -TheStefan-Boltzmann Constant

T= absolute temperature Kelvin (K)

A= area of the emitting body (m^{2})

#### The Stefan-Boltzmann Constant in Imperial Units

σ= 5.6703 10^{-8}(W/m^{2}K^{4})

= 0.1714 10^{-8}( Btu/(h ft^{2}^{o}R^{4}) )

= 0.119 10^{-10}( Btu/(h in^{2 o}R^{4}) )

**Example - Radiation from the surface of the Sun**

If the surface temperature of the sun is* 5800 K* and if we assume that the sun can be regarded as a black body the radiation energy per unit time can be expressed by modifying (1) like

q / A = σ T^{4}= (

5.6703 10^{-8}W/m^{2}K^{4}) (5800 K)^{4}

= 6.42 10^{7}(W/m^{2})

### Gray Bodies and Emissivity Coefficients

For objects other than ideal blackbodies ('gray bodies') the **Stefan-Boltzmann Law** can be expressed as

q = ε σ T^{4}A(2)

where

ε= emissivity of the object (one for a black body)

### For the gray body the incident radiation (also called irradiation) is partly reflected, absorbed or transmitted.

The emissivity coefficient is in the range *0 < **ε** < 1,* depending on the type of material and the temperature of the surface. The emissivity of some common materials

- oxidized Iron at
*390*^{o}F (199^{o}C) >*ε**= 0.64* - polished Copper at
*100*^{o}F (38^{o}C) >*ε**= 0.03* - emissivity coefficients for some common materials

### Net Radiation Loss Rate

If an hot object is radiating energy to its cooler surroundings the net radiation heat loss rate can be expressed as

q = ε σ (T_{h}^{4}- T_{c}^{4}) A_{c}(3)

where

T_{h}= hot body absolute temperature (K)

T_{c}= cold surroundings absolute temperature (K)

A_{c}= area of the object (m^{2})

Heat loss from a heated surface to unheated surroundings with mean radiant temperatures are indicated in the chart below.

### Lambert's cosine law

Heat emission from a surface in an angle *β* can be expressed with Lambert's cosine law as

*q*_{β}* = q cos β (4)*

*where *

*q*_{β}* = heat emission in angle β *

*q = heat emission from the surface*

*β = angle *

Sponsored Links

## Related Topics

## Related Documents

## Tag Search

- en: radiation heat transfer coefficient
- es: radiación coeficiente de transferencia de calor
- de: Strahlungswärme-Übertragungskoeffizient