Hydraulic Pump Volume Capacity

Hydraulic pump capacity can be estimated in Imperial units as

q = 0.26 A s / t                                         (1)

where

q = pump output capacity (gpm)

A = area of cylinder (in²)

s = piston stroke (in)

t = required time for full stroke (s)

• 1 gpm (US) =6.30888x10^-5 m³/s = 0.227 m³/h = 0.06309 dm³(litre)/s = 2.228x10^-3 ft³/s = 0.1337 ft³/min = 0.8327 gpm (UK)
• 1 in (inch) = 25.4 mm = 2.54 cm = 0.0254 m = 0.08333 ft
• 1 in² = 6.452 cm² = 6.452x10^-4 m² = 6.944x10^-3 ft²

Hydraulic pump capacity can be estimated in Metric units as

q = 10^-6 A s / t                                         (2)

where

q = pump output capacity (l/s)

A = area of cylinder (mm²)

s = piston stroke (mm)

t = required time for full stroke (s)

Required pump output for hydraulic cylinders ranging 1 - 6 1/2 inches are indicated below. Multiply pump capacity with stroke length (in).

Example - Required Pump Capacity

A 3" hydraulic cylinder with cylinder area 7.065 in² makes a 30 inches stroke in 3 seconds. The required pump capacity can be calculated

 q = 0.26 (7.065 in²) (30 in) / (3 s)

    = 18.4 gpm        

Hydraulic Pump Volume Capacity Calculator

Imperial Units

A - cylinder area (in²)

s - piston stroke (in)

t - time for full stroke (s)

SI Units

A - cylinder area (mm²)

s - piston stroke (mm)

t - time for full stroke (s)

Temperature ^oC
K
^oF

Length m
km
in
ft
yards
miles
naut miles

Area m²
km²
in²
ft²
miles²
acres

Volume m³
liters
in³
ft³
us gal

Weight kg_f
N
lbf

Velocity m/s
km/h
ft/min
ft/s
mph
knots

Pressure Pa
bar
mm H₂O
kg/cm²
psi
inches H₂O

Flow m³/s
m³/h
US gpm
cfm