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Hydraulic Pumps - Capacities Required
Calculate required hydraulic pump output
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Required hydraulic pump capacity can be calculated as
q = 0.26 A s / t (1)
where
q = pump output capacity (gpm)
A = area of cylinder (square inches)
s = piston stroke (inches)
t = required time for full stroke (s)
- 1 gpm (US) =6.30888x10-5 m3/s = 0.227 m3/h = 0.06309 dm3(litre)/s = 2.228x10-3 ft3/s = 0.1337 ft3/min = 0.8327 gpm (UK)
- 1 in (inch) = 25.4 mm = 2.54 cm = 0.0254 m = 0.08333 ft
- 1 in2 = 6.452 cm2 = 6.452x10-4 m2 = 6.944x10-3 ft2
Required pump output for hydraulic cylinders ranging 1 - 6 1/2 inches are indicated below. Multiply pump capacity with stroke length (in).
Example - Required Pump Capacity
A 3" hydraulic cylinder with cylinder area 7.065 in2 moves a 30 inches stroke in 3 seconds. Required pump capacity can be calculated as
q = 0.26 7.065 (in2) 30 (in) / 3 (s)
= 18.4 gpm
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Related Topics
- Hydraulics and Pneumatics - Hydraulic and pneumatic systems - force, pistons, pumps and fluids
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