Hydraulic Force

The force produced by a double acting hydraulic piston on the rod side can be expressed as

F₁ = π / 4 (d₂² - d₁²) P₁         (1)

where 

F₁ = rod pull force (lb)

d₁ = rod diameter (inches)

d₂ = piston diameter (inches)

P₁ = pressure in the cylinder (rod side) (lf_f/in²)

The force produced opposite the rod can be expressed as

F₂ = π / 4 d₂² P₂         (2)

where 

F₂ = rod push force (lb)

P₂ = pressure in the cylinder (opposite rod) (lf_f/in²)

Calculate Pull Force - with pressure acting on rod side

Calculate Push Force - with pressure acting opposite rod side

Related Mobile Apps from The Engineering ToolBox

• Hydraulic Force Calculator App

- free apps for offline use on mobile devices.

Push Diagram

Rod pushing force for hydraulic cylinders are indicated below: 

• psi (lb/in²) = 144 psf (lb_f/ft²) = 6,894.8 Pa (N/m²) = 6.895x10^-3 N/mm² = 6.895x10^-2 bar
• 1 lb_f (Pound force) = 4.44822 N = 0.4536 kp
• 1 in (inch) = 25.4 mm

Pull Diagram

Rod pulling force for hydraulic cylinders are indicated below:

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