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Hydraulic Force
Hydraulic force - area formulas and calculator
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The force produced by a double acting hydraulic piston on the rod side can be expressed as
F1 = π / 4 (d22 - d12) P1 (1)
where
F1 = rod pull force (lb)
d1 = rod diameter (inches)
d2 = piston diameter (inches)
P1 = pressure in the cylinder (rod side) (lff/in)
The force produced opposite the rod can be expressed as
F2 = π / 4 d22 P2 (2)
where
F2 = rod push force (lb)
P2 = pressure in the cylinder (opposite rod) (lff / in)
Calculate Pull Force - with pressure acting on rod side
Calculate Push Force - with pressure acting opposite rod side
Push Diagram
Rod pushing force for hydraulic cylinders are indicated below:
- psi (lb/in2) = 144 psf (lbf/ft2) = 6,894.8 Pa (N/m2) = 6.895x10-3 N/mm2 = 6.895x10-2 bar
- 1 lbf (Pound force) = 4.44822 N = 0.4536 kp
- 1 in (inch) = 25.4 mm
Pull Diagram
Rod pulling force for hydraulic cylinders are indicated below:
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Related Topics
- Hydraulics and Pneumatics - Hydraulic and pneumatic systems - force, pistons, pumps and fluids
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