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The capture air velocity in distance x from an exhaust outlet can be expressed as
vc = q / (4 π x2)
= vo A / (12 x2)
= vo π d2 / (48 x2) (1)
where
q = air volume flow (m3/s, ft3/s)
A = duct area (m2, ft2)
vc = capture air velocity in distance x from exhaust outlet (m/s, ft/s)
vo = air velocity in the exhaust outlet opening (m/s, ft/s)
d = diameter of exhaust outlet (m, ft)
x = distance from exhaust outlet (m, ft)
Note! According line one of the equation (1) the capture velocity is not dependent on the size of duct. This equation can only be used for exhaust outlets with relatively small diameters.

For larger exhaust outlets equation (1) should be modified to
vc = vo A / (A + 10 x2)
= q / (A + 10 x2) (2)
Capture air velocity in distance 250 mm from a 250 mm duct with internal air velocity of 3 m/s can be calculated as
vc = 3 (m/s) π [0.250 (m)]2 / 48 [0.250 (m/s)]2
= 0.2 m/s
Note! The air velocity in distance one diameter from the duct outlet - is less than 10% of the duct air velocity.
The velocity in distance x from an exhaust outlet can be calculated with the calculators below.

If the exhaust outlet is in a wall or with a flange the evacuation efficiency is improved and can be expressed as
vc = 1.33 vo A / (A + 10 x2)
= 1.33 q / (A + 10 x2) (3)
The calculator above can be used if volume is multiplied with 1.33. Use of exhaust hoods will improve the evacuation efficiency further.
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