# Electrical Heating of a Mass

## Electric heating of object and temperature change

Sponsored Links

When an electric heater heats an object - the electric energy is transformed to heat by increased object temperature. The electric energy used equals the change in thermal energy and can be expressed as:

*U I t μ = c m dT (1)*

*electric energy supplied = thermal energy change in object *

*where*

*U = potential difference (volts, V)*

*I = electrical current (amps, A)*

*t = time (sec)*

*μ = heating efficiency *

*c = specific heat of the heated substance (J/kg. ^{o}C)*

*m = mass of the heated substance (kg)*

*dT = temperature differance ( ^{o}C)*

#### Example - 12 Volt Car Water Heater

The temperature change in a *12 volts* and *10 amps* Car Water Heater (*100% efficient => μ = 1*) with *0.4 kg* water and *5 minutes* heating period can be calculated by modifying *(1)* to

*dT = **V I t μ / c m*

* = (12 volts) (10 amps) (300 sec) 1 / (4200 J/kg. ^{o}C) (0.4 kg)*

* = 21.4 ^{o}C*

**Note!** The mass of the water heater and the heat loss from the heater during heating is neglected in the calculation. In reality the mass of the heater and the heat loss from the heater during the heating process will influence the temperature change.

## Related Topics

Sponsored Links

## Related Documents

Sponsored Links