Cylinders and Pipes - Conductive Heat Losses

Conductive heat losses through cylinder or pipe walls

Cylinder or pipe - heat loss

Uninsulated Cylinder or Pipe

Conductive heat loss through the wall of a cylinder or pipe can be expressed as

Q = 2 π k L (ti - to) / ln(D/ Di)                               (1)

where

Q = heat transfer from cylinder or pipe (W, Btu/hr)

k = thermal conductivity of material (W/mK or W/m oC, Btu/(hr oF ft2/ft))

L = length of cylinder or pipe (m, ft)

to = temperature outside pipe or cylinder (K or oC, oF)

ti = temperature inside pipe or cylinder (K or oC, oF)

ln = the natural logarithm

Do = cylinder or pipe outside diameter (m, ft)

Di = cylinder or pipe inside diameter (m, ft)

Insulated Cylinder or Pipe

Conductive heat loss through an insulated cylinder or pipe can be expressed as

Q = π L (ti - to) / ((rs ln(D/ Di) / 2 k) + (rs ln(Ds / Do) / 2 ks))                          (2)

where 

Ds = outside diameter of insulation (m, ft)

ks = thermal conductivity insulation (W/mK or W/m oC, Btu/(hr oF ft2/ft))

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